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3r^2-2=58.75
We move all terms to the left:
3r^2-2-(58.75)=0
We add all the numbers together, and all the variables
3r^2-60.75=0
a = 3; b = 0; c = -60.75;
Δ = b2-4ac
Δ = 02-4·3·(-60.75)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-27}{2*3}=\frac{-27}{6} =-4+1/2 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+27}{2*3}=\frac{27}{6} =4+1/2 $
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